x^2+(4x-1)+(x+11)+90=180

Solution for x^2+(4x-1)+(x+11)+90=180 equation:

x^2+(4x-1)+(x+11)+90=180

We move all terms to the left:

x^2+(4x-1)+(x+11)+90-(180)=0

We add all the numbers together, and all the variables

x^2+(4x-1)+(x+11)-90=0

We get rid of parentheses

x^2+4x+x-1+11-90=0

We add all the numbers together, and all the variables

x^2+5x-80=0

a = 1; b = 5; c = -80;
Δ = b2-4ac
Δ = 52-4·1·(-80)
Δ = 345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{345}}{2*1}=\frac{-5-\sqrt{345}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{345}}{2*1}=\frac{-5+\sqrt{345}}{2}
$